[TYPO3] Display menu items in pairs

[Ioan Aganencei]

Hi list,

I searched for the last day trying to generate a kind o menu like this 
but didn't find the solution

menu1               menu2                  menu3
    subitem1             subitem1               subitem1
    subitem2             subitem2         menu4
    subitem3        menu3                        subitem1
    subitem4              subitem1               subitem2

The idea is that the first menu should appear in one column and the 
others be grouped in pairs.

I'm trying to wrap each menu in a table, so that's where all that tags 
come from.

I really need a tip on it, because I'm a beginner in Typo3.

Thanks in advance.

My TS for now looks like this:


temp.menu = HMENU
temp.menu.1 = TMENU

temp.menu.1.target = page

temp.menu.1 {
  expAll = 1
  wrap = <table ><tr> | </tr></table>
 
  NO {
    linkWrap = <td> | </td>
    allStdWrap.insertData = 1
   
    allWrap = <td ><table> <tr><td><table><tr> | </tr></table></td></tr>
     
    allWrap.override = <td><table ><tr><td >&nbsp;</td><td><table ><tr> 
| </tr></table></td><td >&nbsp;</td></tr><tr><td ></td></tr>
    allWrap.override.if.value = 25,4
    allWrap.override.if.isInList.field = uid
  }
}

temp.menu.2 = TMENU

temp.menu.2 {
  target = page
  wrap = | </table></td><td >&nbsp;</td>
 
  NO {
    linkWrap= <div > | </div>
    allStdWrap.insertData = 1
   
    allWrap = <tr><td> | </td></tr>
   
    allWrap.override = <tr><td > | </td><td >&nbsp;</td></tr>
    allWrap.override.if.value = 25,4,3,2
    allWrap.override.if.isInList.field = uid

  }
}