[TYPO3-project-formidable] rdt:LISTER with LINK: Adding the UID of the record to the URL
Jerome Schneider
typo3dev at ameos.com
Thu Mar 5 16:10:31 CET 2009
I did not see that Rego had already answered !
Sorry for double answering.
Regards
Jerome
Jerome Schneider a écrit :
> Hi Hauke !
>
> Do it like this:
>
> $aRow = $this->oDataHandler->getListData();
> return $this->cObj->currentPageURL(
> array('preview_pi1[show_preview]' => $aRow['uid'])
> );
>
>
> Regards,
> Jerome Schneider
>
> Hauke Hain a écrit :
>> Hello,
>>
>> I have titles in my lister and I want to make a link where the uid of
>> the record is a URL parameter.
>> The problem is to get the UID. Her is the relevant part of my XML-file:
>>
>> [...]
>> <datasources>
>> <datasource:DB name="pages">
>> <sql>
>> <userobj>
>> <php><![CDATA[
>> return 'SELECT r.title FROM preview_previews WHERE pid =
>> '.$GLOBALS['TSFE']->id.' AND r.deleted=0 AND r.hidden=0';
>> ]]></php>
>> </userobj>
>> </sql>
>> </datasource:DB>
>> </datasources>
>>
>> </control>
>> <elements>
>> <renderlet:LISTER name="allreviews" cachehash="true"
>> custom="scope='col'">
>> <datasource use="pages" />
>> <template
>> path="/typo3conf/ext/preview/res/tmpl/list_previews.html"
>> subpart="###MAIN###"
>> cssfile="/typo3conf/ext/preview/res/lister.css"
>> alternaterows="###ROW1###, ###ROW2###"/>
>> <columns>
>> <column name="title" type="renderlet:LINK"
>> listHeader="LLL:listAll.title">
>> <href><userobj><php><![CDATA[
>> $aParams = ''; // From where??
>> return $this->cObj->currentPageURL(
>> array('preview_pi1[show_preview]' => $aParams['uid']));
>> ]]></php></userobj></href>
>> </column> </column>
>> </columns>
>> </renderlet:LISTER>
>> [...]
>>
>> It is possible to get the uid for AJAX events, but how can I reach my
>> goal?
>>
>> Regards,
>> Hauke
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