[TYPO3-project-formidable] rdt:LISTER with LINK: Adding the UID of the record to the URL
Jerome Schneider
typo3dev at ameos.com
Thu Mar 5 16:09:33 CET 2009
Hi Hauke !
Do it like this:
$aRow = $this->oDataHandler->getListData();
return $this->cObj->currentPageURL(
array('preview_pi1[show_preview]' => $aRow['uid'])
);
Regards,
Jerome Schneider
Hauke Hain a écrit :
> Hello,
>
> I have titles in my lister and I want to make a link where the uid of
> the record is a URL parameter.
> The problem is to get the UID. Her is the relevant part of my XML-file:
>
> [...]
> <datasources>
> <datasource:DB name="pages">
> <sql>
> <userobj>
> <php><![CDATA[
> return 'SELECT r.title FROM preview_previews WHERE pid =
> '.$GLOBALS['TSFE']->id.' AND r.deleted=0 AND r.hidden=0';
> ]]></php>
> </userobj>
> </sql>
> </datasource:DB>
> </datasources>
>
> </control>
> <elements>
> <renderlet:LISTER name="allreviews" cachehash="true" custom="scope='col'">
> <datasource use="pages" />
> <template
> path="/typo3conf/ext/preview/res/tmpl/list_previews.html"
> subpart="###MAIN###"
> cssfile="/typo3conf/ext/preview/res/lister.css"
> alternaterows="###ROW1###, ###ROW2###"/>
> <columns>
> <column name="title" type="renderlet:LINK"
> listHeader="LLL:listAll.title">
> <href><userobj><php><![CDATA[
> $aParams = ''; // From where??
> return $this->cObj->currentPageURL(
> array('preview_pi1[show_preview]' => $aParams['uid']));
> ]]></php></userobj></href>
> </column> </column>
> </columns>
> </renderlet:LISTER>
> [...]
>
> It is possible to get the uid for AJAX events, but how can I reach my goal?
>
> Regards,
> Hauke
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