[TYPO3-project-formidable] Dynamically pass the cruser_id to the SQL of the datasource
Ian Solo
ian at webian.it
Fri May 9 14:23:42 CEST 2008
Thank you so much Manuel!
It works like a sharm. =)
Best regards!ian
Manuel Rego Casasnovas wrote:
> Hi,
>
> On Thu, 2008-05-08 at 11:45 +0200, Ian Solo wrote:
>> I have a renderlet:LISTER that get the data from this datasource:
>> *****************************************************************
>> <datasources>
>> <datasource:DB name="images">
>> <sql><![CDATA[
>> SELECT uid, image, title, tstamp, crdate
>> FROM tx_iangallery_gallery
>> WHERE pid = 301
>> AND cruser_id = 81
>> AND deleted=0
>> AND hidden=0
>> ]]></sql>
>> </datasource:DB>
>> </datasources>
>> *****************************************************************
>>
>> How can I dynamically pass the cruser_id of the current user logged to
>> this SQL?
>
> You can use an userobj that return the SQL query from a function:
> <datasource:DB name="images">
> <sql>
> <userobj>
> <extension>this</extension>
> <method>_generateSQL</method>
> </userobj>
> </sql>
> </<datasource:DB>
>
> or directly from PHP:
> <datasource:DB name="images">
> <sql>
> <userobj>
> <php>
> <![CDATA[
> $cruserId = 81;
> return 'SELECT uid, image, title, tstamp, crdate
> FROM tx_iangallery_gallery
> WHERE pid = 301
> AND cruser_id = ' . $cruserId . '
> AND deleted=0
> AND hidden=0';
> ]]>
> </php>
> </userobj>
> </sql>
> </<datasource:DB>
>
> Best regards,
> Rego
>
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