[TYPO3] ul/li menu question

[Edwin Blokker]

Hello,

I'm trying to implement a multilevel css / unordered lists based menu, 
using templavoila. This is the HTML:

<ul class="vnavv">
	<li class="vlevel1act">
		<a href="skidoo_too.css">skidoo_too.css</a>
		<ul class="vlevel2act">
			<li>
				<a href="iets">Iets</a>
			</li>
		</ul>
		<ul class="vlevel2no">
			<li>
				<a href="iets">Nogmaals heel normaal</a>
			</li>
		</ul>
	</li>
	<li class="vlevel1no">
		<a href="skidoo_too_print.css">skidoo_too_print.css</a>
	</li>
</ul>


And this is the typoscript I use:

# Horizontal menu cObject
lib.hnavv = HMENU
   # First level menu-object, textual
lib.hnavv.1 = TMENU
lib.hnavv.1 {
     # Normal state properties
   NO.allWrap = <li class="hlevel1no">|<span class="divider"> : </span></li>
   NO.stdWrap.htmlSpecialChars = 1
    # Enable active state and set properties:
   ACT = 1
   ACT.stdWrap.htmlSpecialChars = 1
   ACT.allWrap = <li class="hlevel1act">|<span class="divider"> : 
</span></li>
}

# Vertical menu cObject
lib.vnavv = HMENU
lib.vnavv.entryLevel = 1
   # First level menu-object, textual
lib.vnavv.1 = TMENU
lib.vnavv.1 {
     # Normal state properties
   NO.allWrap = <li class="vlevel1no">|</li>
   NO.stdWrap.htmlSpecialChars = 1
    # Enable active state and set properties:
   ACT = 1
   ACT.stdWrap.htmlSpecialChars = 1
   ACT.allWrap = <li class="vlevel1act">|</li>

}
# Second level menu-object, textual
lib.vnavv.2 = TMENU
lib.vnavv.2 {
     # Normal state properties
   NO.allWrap = <li class="vlevel2no">|</li>
   NO.stdWrap.htmlSpecialChars = 1
     # Enable active state and set properties:
   ACT = 1
   ACT.stdWrap.htmlSpecialChars = 1
   ACT.allWrap = <li class="vlevel2act">|</li>
}


The problem is that when the page is rendered, the second menu level 
isn't wrapped in seprate UL tags, so it just becomes a list item instead 
of a sublist and is rendered like a first level menu item. I really 
don't know how to solve this, I've read the basic tutorials and this is 
my first attempt. Any help or tips would be appreciated!

Edwin.