[TYPO3] How to create "Current menu item foldout menu" ?

[Jan Zýka]

Thanks for help, but, infortunatelly, still cant manage it. Saw zounds of
examples and it is still the same. I use:

temp.mainTemplate.subparts.LEFT_MENU = COA
temp.mainTemplate.subparts.LEFT_MENU {

 2 = HMENU
 2.special = directory
 2.special.value = {$leftTopMenuRootId}
 2.1 = TMENU
 2.1.NO.linkWrap =<li class="leftMenuItem">|</li>
 2.1.NO.ATagBeforeWrap = 0
 2.1.ACT = 1
 2.1.ACT.linkWrap=<li class="leftMenuItem">|</li>
 2.1.ACT.ATagBeforeWrap = 0

 2.2 = TMENU
 2.2.expAll=1
 2.2.NO.linkWrap =<li class="leftMenuItem2ndLevel">|</li>
 2.2.NO.ATagBeforeWrap = 0
 2.2.ACT = 1
 2.2.ACT.linkWrap = <li class="leftMenuItem2ndLevel">|</li>
 2.2.ACT.ATagBeforeWrap = 0
}

Still, until I put there expAll = 1 the submenu for the active item get
never folded out. When I put expAll = 1 in, all the submenus are allways
folded out. Could anybody give me example of functional code? Please dont
advice me to google for solution, because I did, for hours - believe me, and
I am starting to get crazy. Thanks in advance.