[TYPO3] Partial menu generation
Jeppe Vesterbæk
jhve02 at control.aau.dk
Thu Feb 16 00:23:34 CET 2006
Hi,
Suppose I have a tree structure like this:
- Page ID=1 (level 1)
- Page ID=2 (level 1)
- Page ID=3 (level 2)
- Page ID=4 (level 2)
-Page ID=5 (level 3)
-Page ID=6 (level 3)
-Page ID=3 (level 1)
How do I dynamically generate a new menu given a page ID? Say we want a
menu with ID=4 as pageroot, this menu shold look like (example 1):
- Page ID=4 (level 1)
-Page ID=5 (level 2)
-Page ID=6 (level 2)
or if menu root is ID=2 and selected page is ID=6, show this menu
(example 2):
- Page ID=2 (level 1)
- Page ID=3 (level 2)
- Page ID=4 (level 2)
-Page ID=5 (level 3)
-Page ID=6 (level 3)
I'm doing this way:
temp.menu_doc.special = list
temp.menu_doc.special.value={GPvar:menuroot}
temp.menu_doc.special.value.insertData = 1
temp.menu_doc.entryLevel=0
[globalVar = GP:menuentrylevel = 1]
temp.menu_doc.entryLevel=1
[globalVar = GP:menuentrylevel = 2]
temp.menu_doc.entryLevel=2
[globalVar = GP:menuentrylevel = 3]
temp.menu_doc.entryLevel=3
[globalVar = GP:menuentrylevel = 4]
temp.menu_doc.entryLevel=4
[global]
So, to generate my menu in (example 1), my query string looks like:
index.php?id=5&menuroot=4&menuentrylevel=1
To generate the menu in (exampe 2), my query string look like
index.php?id=6&menuroot=2&menuentrylevel=0
This solution DOES WORK! BUT, it is not a nice solution because:
1) I need to know the entrylevel of the menuroot page
2) Quote TSREF p. 72: "NOTE: Don't set .entryLevel for a HMENU when
using this option!"
But I need to set the entrylevel because (also from TSREF p. 72): "Also
be aware that this selects pages for the first level in
the menu. Submenus by menuPbjects 2+ will be created as usual."
To sum up, what I want to do is the specify a page ID in the query
string that defined the new "menuroot".
Comments?
Thanks,
Jeppe Vesterbaek
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