[TYPO3-project-formidable] rdt:LISTER with LINK: Adding the UID of the record to the URL

[Hauke Hain]

Hello,

I have titles in my lister and I want to make a link where the uid of the 
record is a URL parameter.
The problem is to get the UID. Her is the relevant part of my XML-file:

[...]
   <datasources>
   <datasource:DB name="pages">
    <sql>
          <userobj>
            <php><![CDATA[
          return 'SELECT r.title FROM preview_previews WHERE pid = 
'.$GLOBALS['TSFE']->id.' AND r.deleted=0 AND r.hidden=0';
        ]]></php>
          </userobj>
        </sql>
   </datasource:DB>
  </datasources>

 </control>
 <elements>
 <renderlet:LISTER name="allreviews" cachehash="true" custom="scope='col'">
   <datasource use="pages" />
   <template
          path="/typo3conf/ext/preview/res/tmpl/list_previews.html"
          subpart="###MAIN###"
          cssfile="/typo3conf/ext/preview/res/lister.css"
          alternaterows="###ROW1###, ###ROW2###"/>
   <columns>
    <column name="title" type="renderlet:LINK" 
listHeader="LLL:listAll.title">
      <href><userobj><php><![CDATA[
      $aParams = ''; // From where??
      return $this->cObj->currentPageURL(
                  array('preview_pi1[show_preview]' => $aParams['uid']));
          ]]></php></userobj></href>
    </column>    </column>
   </columns>
  </renderlet:LISTER>
[...]

It is possible to get the uid for AJAX events, but how can I reach my goal?

Regards,
Hauke