[TYPO3-english] Typo3 foreign_table: How to specify a specific column to a select drop down menu?

[Mikel]

Do you need something like that?
'foreign_table_where' => 'AND tx_icingaconfgen_domain_model_kunde.your_property = ###REC_FIELD_[tx_icingaconfgen_your_model_to_compare.your_property]###‘,

Sorry, but I’m not sure if I understand your use case. It is a bit hard to read :-)

You can also have a look on https://docs.typo3.org/typo3cms/TCAReference/ColumnsConfig/Type/Select.html#itemsprocfunc <https://docs.typo3.org/typo3cms/TCAReference/ColumnsConfig/Type/Select.html#itemsprocfunc>
You can prepare the items for the select in your own method.

Mikel


> Am 24.10.2017 um 15:04 schrieb christian ewigfrost <christian-kulozik at gmx.net>:
> 
> Hmmm... But that's not waht i want to do: What this does is just filtering the assignable records by their properties and then lets me choose the record in the select. But it assigns the entire record or the uid of the record to the property of the creatable record as understand. 
> What i want to do is:
> 
> Say i'd set 'kundeuid' with the value 'customer01' or something while creating a record of the class Kunde. Then i create a record of the class 'Appliance'. It also has a property named 'kundeuid' and i want to set it through a select that is filled with the 'kundeuid' s from all the records of the class Kunde. One option of this select would be 'customer01' from the record of Kunde i created. I'd choose it and the property 'kundeuid' of the created Appliance record should be also 'customer01'... _______________________________________________
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