[TYPO3] Sitemap can't be rendered with css in typo3 4.0?
Matyi Gábor
gmatyi at freemail.hu
Mon May 15 21:35:35 CEST 2006
2006. május 15. 20.25 dátummal Harald Klotzberg ezt írta:
> Hi Matyi,
>
> use the standard Typo Sitmap with this in your TS-Setup and it should
> work
>
> # SITEMAP Wrap
> tt_content.menu.20.entryLevel = -1
> tt_content.menu.20.2.1.wrap = <ul class="l1">|</ul>
> tt_content.menu.20.2.2.wrap = <ul class="l2">|</ul>
> tt_content.menu.20.2.3.wrap = <ul class="l3">|</ul>
> tt_content.menu.20.2.4.wrap = <ul class="l4">|</ul>
> tt_content.menu.20.2.5.wrap = <ul class="l5">|</ul>
> tt_content.menu.20.2.6.wrap = <ul class="l6">|</ul>
> tt_content.menu.20.2.7.wrap = <ul class="l7">|</ul>
>
Thanks. First I saw with the object browser my root template. I see this.
tt_content.menu = CASE
tt_content.menu.1 = HMENU
tt_content.menu.1.wrap = <div class="csc-menu csc-menu-1">|</div>
tt_content.menu.2 = HMENU
tt_content.menu.2.wrap = <div class="csc-menu csc-menu-2">|</div>
tt_content.menu.2.1 = TMENU
tt_content.menu.2.1.NO.allWrap = <p class="csc-sitemap
csc-sitemap-level1">|</p>
tt_content.menu.2.2.NO.allWrap = <p class="csc-sitemap
csc-sitemap-level2">|</p>
tt_content.menu.2.2 = TMENU
tt_content.menu.2.3 = TMENU
tt_content.menu.2.4 = TMENU
tt_content.menu.3 = CONTENT
tt_content.menu.3.wrap = <div class="csc-menu csc-menu-3">|</div>
..
..
..
This means, that my tt_content.menu is configured. What I don't understand,
if I create a sitemap page content why don't put the sitemap these <div
class="csc-menu csc-menu-1"> to my generated html file. I see just this
<div class="csc-sitemap">.
But this row is missing. : tt_content.menu.20.entryLevel = -1
What does this do?
Thanks Gabor Matyi
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