[Typo3] Problem with RTE and style rendering
A-san
amir219 at sbcglobal.net
Sat Oct 29 17:29:25 CEST 2005
Olivier Dobberkau wrote:
> A-san wrote:
>
>> Yeah, I tried pretty much everything in that wiki and yet the lists
>> still dont show properly. :(
>
>
> what happens with this in your ts setup?
>
> # Bullet lists
> #
> # RTE default
> #
>
> tt_content.text.20.parseFunc.tags.typolist.default {
> wrap = <ul> | </ul>
> split.1.wrap = <li> | </li>
> }
>
> tt_content.text.20.parseFunc.tags.typolist.1 {
> fontTag = <ul class="layout1"> | </ul>
> split.1.wrap = <li class="layout1"> | </li>
> textStyle >
> }
>
> tt_content.text.20.parseFunc.tags.typolist.2 {
> fontTag = <ul class="layout2"> | </ul>
> split.1.wrap = <li class="layout2"> | </li>
> textStyle >
> }
>
> tt_content.text.20.parseFunc.tags.typolist.3 {
> fontTag = <ul class="layout3"> | </ul>
> split.1.wrap = <li class="layout3"> | </li>
> textStyle >
> }
>
> tt_content.text.20.parseFunc.tags.typolist.4 {
> fontTag = <ul class="layout4"> | </ul>
> split.1.wrap = <li class="layout4"> | </li>
> textStyle >
> }
>
> # BULLETS default
> #
> tt_content.bullets.20.default {
> wrap = <ul> | </ul>
> split.1.wrap = <li> | </li>
> }
>
> tt_content.bullets.20.1 {
> fontTag = <ul class="layout1"> | </ul>
> split.1.wrap = <li class="layout1"> | </li>
> split.1.textStyle >
> }
>
> tt_content.bullets.20.2 {
> fontTag = <ul class="layout2"> | </ul>
> split.1.wrap = <li class="layout2"> | </li>
> split.1.textStyle >
> }
>
> tt_content.bullets.20.3 {
> fontTag = <ul class="layout3"> | </ul>
> split.1.wrap = <li class="layout3"> | </li>
> split.1.textStyle >
> }
>
> add
>
> RTE.default.proc.typolist = 0
>
> to your page TS Setup
>
> olivier
Alright, I copied and pasted that set of ts to my template file..
then I put this in the ts config:
RTE.default.proc.typolist = 0
Nothing changed. Did I do this right?
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